Volume to Volume Stoichiometry

 

A volume to volume probelm is one in which the volume of a reactant or product is given. You are then asked to calculate the volume of another reactant required or the mass of another product formed.

Example 1:

Nitrogen and hydrogen react to produce ammonia. What volume of ammonia could be produced from 300 liters of nitrogen at 200°C and 150 kPa? Assume that enough hydrogen is available for a complete reaction.

Sample solution:

Step 1

Write a balanced chemical equation and the number of moles and the volumes of all the substances in the equation.

N2	+	3 H2	----->	2 NH3
1 mol		3 mol		2 mol
22.4 L (STP)				2 (22.4) L (STP)

Step 2

Write the given value and "X" for the unknown beneath the appropriate substance.

N2	+	3 H2	----->	2 NH3
1 mol		3 mol		2 mol
22.4 L (STP)				2 (22.4) L (STP)
300 L at 473K and 150 kPa				X L at 473K and 150 kPa

Step 3

Set up a ratio.

22.4 L (STP)	=	2 (22.4) L (STP)
300 L (at 473K and 150 kPa)		X L (at 473K and 150 kPa)

Step 4

Solve for "X". Use cross multiplication.

22.4 L(STP) x X L(473K, 150kPa) = 300 L x 2 (22.4) L (STP)

X = 600 L

Therefore 600 L of ammonia gas will form at 200°C and 150 kPa .

Next page of tutorial (Mass to Volume Stoichiometry)

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