Mass to Mass Stoichiometry

 

A mass to mass probelm is one in which the mass of a reactant or product is given. You are then asked to calculate the mass of another reactant required or the mass of another product formed.


Example 1:

How many grams of oxygen are required to burn 12.9 grams of propane, C3H8?

Sample solution:

Step 1

Write the equation, the moles and masses of the substances beneath the required substances.

 C3H8

 +

  5O2
 ----->  3 CO2  +  4 H2O

 1 mole

 

 5 moles
       

 44 g

 

 5 (32) g
       

Step 2

Write the given value (12.9 g propane) and "X" for the unknown (oxygen) beneath the appropriate substance.

 C3H8

 +

  5O2
 ----->  3 CO2  +  4 H2O

 1 mole

 

 5 moles
       

 44 g

 

 5 (32) g
       

 12.9 g

 

 X
       

Step 3

Set up a ratio.

 44 g

 =
 5 (32)g

 12.9 g

    X

Step 4

Solve for "X". Use cross multiplication.

44 g x X g = 12.9 g x 160 g

X = (2064 g ) / 44 g
= 46.9 g

Therefore 12.9 grams of propane will produce 46.9 grams of oxygen.

Example 2:

Nitrogen and hydrogen react to produce ammonia. What mass of ammonia could be produced from 500 grams of nitrogen? Assume that enough hydrogen is available for a complete reaction.

Sample solution:

Step 1

Write a balanced chemical equation and the number of moles and the masses of all the substances in the equation.

 _ N2   +  _ H2  ----->  _ NH3
  mol         mol
  g        g

Step 2

Write the given value and "X" for the unknown beneath the appropriate substance.

 _ N2   +  _H2  -----> _ NH3

 28 g
 

 _ (2 ) g
 

  _ ( 17 ) g
         

Step 3

Set up a ratio.

 

 =

 


Step 4

Solve for "X". Use cross multiplication.

Therefore X =

Therefore 500 grams of nitrogen will produce grams of ammonia.

 

For some more problems click here.

Next page of tutorial (Mass to Molecule Stoichiometry)

 

Back to Table of Contents
Science Home Page
Ms. D. Bilic's Home Page
Applewood Heights Secondary School

E-mail me at: dbilic@interlog.com